Question

Guided practiceTopic: Chords and Arcs Geometry BA. 50B. 18C. 36D. 25

Answer 1

We know that the chord is 25 units long.

Also, according to the image, side 18 and half of the given chord from a right triangle. Let's find the hypothenuse with Pythagorean's Theorem.

`\begin{gathered} r^2=18^2+25^2 \\ r=\sqrt[]{324+625}=\sqrt[]{949} \end{gathered}`

Now, we use Pythagorean's theorem to find half of the chord x.

`\begin{gathered} (\sqrt[]{949})^2=((x)/(2))^2+18^2 \\ 949-324=((x)/(2))^2 \\ 625=((x)/(2))^2 \\ (x)/(2)=\sqrt[]{625}=25 \\ x=2\cdot25=50 \end{gathered}`

Therefore, x is 50 units long. A is the right answer.