Question

What is the force on an object that has an impulse of 12.1 N*s and the time it moves is 5.1 seconds?

Answer 1

The force on an object with an impulse of 12.1 N*s over 5.1 seconds is approximately 2.37 N, determined by the impulse equation J = FΔt.

Step-by-step explanation:

To determine the force exerted on an object that has an impulse of 12.1 N*s and moves for 5.1 seconds, we can use the relationship given by the impulse equation, J = FΔt, where J is the impulse, F is the average force exerted, and Δt is the time over which the force is applied. To solve for F, we rearrange the equation as F = J / Δt. Substituting the given values, we get F = 12.1 N*s / 5.1 s, which results in an average force of approximately 2.37 N.

To determine the force on an object, we can use the formula:

Impulse = Force * Time

Given that the impulse is 12.1 N*s and the time is 5.1 seconds, we can rearrange the formula to solve for force:

Force = Impulse / Time

Substituting the given values into the formula:

Answer 2

the formula to calculate the impulse is

`J=Ft`

Where J is the impulse, F is the force, t is time

In our case we have

J=12.1 N*s

t=5.1 s

We substitute

`12.1=F(5.1)`

Then we isolate

`F=(12.1)/(5.1)=2.37\text{ N}`

ANSWER

2.37N3