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The sum of 3 consecutive odd numbers is 147. what is the smallest of the 3 numbers?

1 Answer

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x+y+z=147
y=x+2
z=y+2
x+y+y+2=147
x+x+2+x+2+2=147
3x+6=147
3x=141
x=47
The smallest of the consecutive numbers is 47
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