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V1 = 5 L P1 = 0.5 atm V2 = 2.5 L P2 = ..........

V1 = 5 L P1 = 0.5 atm V2 = 2.5 L P2 = ..........-example-1
User Sebas Sierra
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1 Answer

21 votes
21 votes

Answer

1 atm

Step-by-step explanation

Given:

V₁ = 5 L P₁ = 0.5 atm V₂ = 2.5 L P₂ = ?

According to Boyle's law, the pressure (P) of a given quantity of gas varies inversely with its volume (V) at constant temperature; i.e., in equation form,

P₁V₁ = P₂V₂

So substitute the given values into the equation to get P₂

0.5 atm x 5 L = P₂ x 2.5 L

2.5 atm.L = P₂ 2.5 L

Divide both sides by 2.5 L


\begin{gathered} \frac{2.5\text{ atm}\cdot L}{2.5\text{ L}}=\frac{P_(2)2.5\text{ L}}{2.5\text{ L}} \\ P_(2)=1\text{ atm} \end{gathered}

User Kyo
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