we have a system of inequalities
2x + y ≤ 10 -------> y ≤-2x+10
The solution of the first inequality is the shaded area below the solid line y=-2x+10
2x − 4y < 8 ----> -4y <-2x+8 -----> y> (1/2)x-2
the solution of the second inequality is the shaded area above the dashed line
y=(1/2)x-2
Remember that
If an ordered pair is a solution to the system of inequalities, then the ordered pair must lie on the shaded region of the solution of the system
Using a graphing tool
the solution is the shaded region
therefore
D, A, C are solutions
Verify k and H
If an ordered pair is a solution, then must satisfy both inequalities
Verify point K(2,3)
inequality 1
3 ≤-2(2)+10
3≤6 ----> is true (satisfy inequality 1)
Inequality 2
3> (1/2)(2)-2
3>-1 -----> is true (satisfy inequality 2)
that means
point K is a solution too
Verify point H(-4,-4)
Inequality 1
-4≤-2(-4)+10
-4≤18 ---> is true (satisfy inequality 1)
Inequality 2
-4> (1/2)(-4)-2
-4>-4 ----> is not true (not satisfy the inequality 2)
therefore
point H is not a solution
therefore
the answer is
D, A, C, K
option a