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How would u do this w/o plugging in numbers? Thanks for your time and help!

How would u do this w/o plugging in numbers? Thanks for your time and help!-example-1
User Shalaya
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1 Answer

7 votes
If you know calculus, you can take the derivative and find the critical point.

The simpler method would be to complete the square. We have


R=-\frac1{800}(x^2-2400x)=-\frac1{800}(x^2-2400x+1200^2-1200^2)

R=-\frac1{800}\left((x-1200)^2-1200^2\right)=-\frac1{800}(x-1200)^2+(1200^2)/(800)

The first term will always be negative, so whenever it vanishes, we're left with the maximum value at
(1200^2)/(800)=1800, so the answer is C.