Question

How do you do circuit 7 of Q2, the current in each arm of the circuit?

Answer 1

55Ω

I = 0.22 amp

Explanation:

We are divided into two parts, the first is to solve the parallel system, like this:

`\begin{gathered} (1)/(R_T)=(1)/(R_1)+(1)/(R_2) \\ \text{ replacing:} \\ (1)/(R_T)=(1)/(10)+(1)/(10) \\ R_T=(100)/(10+10)=(100)/(20)=5\Omega \end{gathered}`

Then we have a series system, therefore, we solve like this:

`R_T=5+50=55\Omega`

The first thing is to calculate the current, knowing that the voltage is equal to 12V, like this:

`\begin{gathered} I=(V)/(R)=(12)/(55) \\ I=0.22\text{ amp} \end{gathered}`