Question

The centers of a 15 kg lead ball and a 90 g lead ball are separated by 11 cm. part a what gravitational force does each exert on the other?

Answer 1

`7.441 * 10^(-9) Newtons`

Step-by-step explanation:

Because we know that the forces of one onto the other will be the same, we can use the equation:

`F_(1on2)=F_(2on1)=(Gm_(1)m_(2) )/(r^(2) )`

G is the constant, 6.67 x 10^-11

Plugging, we get:

`((6.67 * 10^(-11))(15kg)(.090kg))/(0.011^(2) )`

=
`7.441 * 10^(-9)N`

Answer 2

The gravitational force between the two objects is calculated through the equation,

F = Gm₁m₂/d²

where F is the gravitational force, G is constant (equal to 6.67 x 10^-11), m₁ and m₂ are masses in kg and d is distance is meters.

Substituting the known values,

F = (6.67 x 10^-11)(15 kg)(0.090 kg)/ (0.11 m)²

F = 7.441 x 10^-9 N

ANSWER: 7.441 x 10^-9 N