Question

15 POINTS!!!!!!! What is the equation of the line in slope-intercept form? Line on a coordinate plane. Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.

Answer 1

The equation of the line in slope-intercept form is y = (4 / 3)x + 4.

Step-by-step explanation:

The equation of a line in slope-intercept form is y = mx + b, where m represents the slope of the line and b represents the y-intercept.

Given the points (-3, 0) and (0, 4), we can find the slope by using the formula m = (y2 - y1) / (x2 - x1). Substituting the values, we get m = (4 - 0) / (0 - (-3)) = 4 / 3.

Now, we can substitute the slope and one of the given points into the slope-intercept form to solve for b. Using the point (-3, 0), we get 0 = (4 / 3) * (-3) + b. Solving for b, we find b = 4.

Therefore, the equation of the line in slope-intercept form is y = (4 / 3)x + 4.

Answer 2

`y=(4)/(3)x+4` is the equation of line in slope intercept form.

Step-by-step explanation:

Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.

First ordered pair: (-3,0)

Second ordered pair: (0,4)

We have two points and need to find equation of line in slope intercept form

`\text{Slope (m)}=(y_2-y_1)/(x_2-x_1)`

`\text{Slope (m)}=(4-0)/(0-(-3))=(4)/(3)`

y-intercept, when x=0 , (0,4)

Equation of line in slope intercept form:

y=mx+b

where,
`m=(4)/(3)` and b=4

Required equation:

`y=(4)/(3)x+4`

Thus,
`y=(4)/(3)x+4` is the equation of line in slope intercept form.