Question

How many moles of nitrogen N are in 71.0g of nitrous oxide , N2O

Answer 1

1.6 moles of N2 in 71g

Answer 2

Answer : The number of moles of nitrogen present in nitrous oxide are 3.22 moles.

Explanation : Given,

Mass of
`N_2O` = 71.0 g

Molar mass of
`N_2O` = 44 g/mole

First we have to calculate the moles of
`N_2O`.

`\text{ Moles of }N_2O=\frac{\text{ Mass of }N_2O}{\text{ Molar mass of }N_2O}=(71.0g)/(44g/mole)=1.61moles`

Now we have to calculate the moles of nitrogen in nitrous oxide.

In nitrous oxide
`N_2O`, there are 2 moles of nitrogen and 1 mole of oxygen.

As, 1 moles of
`N_2O` contains 2 moles of nitrogen

So, 1.61 moles of
`N_2O` contains
`1.61* 2=3.22moles` of nitrogen

Therefore, the number of moles of nitrogen present in nitrous oxide are 3.22 moles.