Question

with the balanced equation : 4Fe + 3O2 = 2Fe2O3How many grams of Fe2O3 is produced when you start with 0.89 moles of iron?

Answer 1

72.66g of Fe2O3 are produced.

Step-by-step explanation:

1st) From the balanced equation we know that 2 moles of Fe2O3 are produced from 4 moles of iron (Fe). With a mathematical rule of three we can calculate the moles of Fe2O3 that will be produced from 0.89 moles of iron:

`\begin{gathered} 4molesFe-2molesFe_2O_3 \\ 0.89molesFe-x=(0.89molesFe*2molesFe_2O_3)/(4molesFe) \\ x=0.445molesFe_2O_3 \end{gathered}`

Now we know that 0.455 moles of Fe2O3 are produced.

2nd) Now we have to convert 0.455 moles of Fe2O3 into grams, by using the molar mass of Fe2O3 (159.7g/mol):

`0.455moles*(159.7g)/(1mole)=72.66g`

So, 72.66g of Fe2O3 are produced.