P(t) = 6 ( 1.025 ) ^t
Let p(t) = 12 since the equation is given in billions
12 = 6 ( 1.025 ) ^t
Divide each side by 6
12/6 = 6/6 ( 1.025 ) ^t
2 = ( 1.025 ) ^t
Now take the natural log of each side
ln(2) = ln( ( 1.025 ) ^t)
Using the exponent rule ln( a^b) = b ln a
ln (2) = t ln ( 1.025)
Divide each side by ln(1.025)
ln (2) / ln(1.025) = t
28.01703= t
Rounding to the nearest year
28 years from the start
The start was 1995
1995+28 = 2023
The year would be 2023