Question

Which of the following equations is equivalent to 4[x + 2(3x – 7)] = 22x – 65?

28x – 7 = 22x – 65

28x – 56 = 22x – 65

10x – 14 = 22x – 65

16x – 28 = 22x – 65

Answer 1

4[x + 2(3x - 7)] = 22x - 65

4[x + 6x - 14] = 22x - 65

4x + 24x - 56 = 22x - 65

28x - 56 = 22x - 65

Answer 2

Answer:
`28x-56= 22x - 65`

Explanation:

The given expression:
`4[x + 2(3x - 7)] = 22x - 65`

Consider L.H.S.
`4[x + 2(3x -7)]`

Solving the bracket present inside by using distributive property, we get

`4[x + 6x -14]=4[7x-14]`

Now, Multiplying 4 inside the bracket by using distributive property:-

`28x-56`

Hence, the given function is equivalent to
`28x-56= 22x -65`