Question

The impedance of an inductor zind is determined to be 147 ohms at 2000 hz and its dc resistance rl is 25 ohms. what would be the inductance of the inductor?

Answer 1

The formula for inductance X is X=2*pi*freq*L. With the given information, we solve for L. The equation becomes: L = X/(2*pi*freq). Substituting the known variables gives us L = 147ohms / (2*pi*2000hz). Solving for L, L equals .0117. The inductance of this inductor is 11.7 mH.