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How many grams of lead(ii) chloride is produced if 13.87 g lead(ii) nitrate combines with excess hydrochloric acid to produce lead(ii) chloride and nitric acid?
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How many grams of lead(ii) chloride is produced if 13.87 g lead(ii) nitrate combines with excess hydrochloric acid to produce lead(ii) chloride and nitric acid?

User Nat Kuhn
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2 Answers

5 votes

Answer:

Pb(NO3)2+2HCl=PbCl2+2HNO3

Step-by-step explanation:

User BitQueen
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Answer: Pb(NO3)2+2HCl=PbCl2+2HNO3 Step 2 Find # of moles of Pb 13.87g Pb(NO3)2 x 1 mol/331.22=.041875 mol Pb(NO3)2 Step 3 Use balanced equation to find weight of Pb(NO3)2 .041875mol Pb x 1 mol Cl2/1mol Pb x 70.90g/1 mol Cl2=2.9689g Cl2 .041875 mol Pb x 207.2/1mol Pb=8.6765g Pb =11.65g
User Lenny Sirivong
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