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What is the van’t Hoff factor for NaCl if it completely dissociates in water?

User Corsaro
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Answer:

2 is the van’t Hoff factor for NaCl if it completely dissociates in water.

Explanation:

Formula used :


\alpha =(i-1)/(n-1)


\alpha = Degree of dissocation.

n = number of ions produced by dissociation of ionic compound

i = van't Hoff factor

We have:


NaCl(aq)\rightarrow Na^+(aq)+Cl^-(aq)

n = 2.
\alpha = 100\%=1


1=(i-1)/(2-1)

i = 2

2 is the van’t Hoff factor for NaCl if it completely dissociates in water.

User Kwolf
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NaCl is a compound that will dissociate into one Na- and one Cl+ ion in water. Because the Van't Hoff factor of an ionic compound is equivalent to the number of ions in the ionic formula, the Van't Hoff Factor is two.
User Vulpo
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