Question

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

Answer 1

When y=32, x=16.5

Explanation:

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

We are given:

x varies inversely with y

We can write it as:
`x\:\alpha \:(1)/(y)`

`x=(k)/(y)`

We have x = 132, when y=4

We can find value of k by using these values

`x=(k)/(y)\\132=(k)/(4)\\k=132*4\\k=528`

We need to find x when y=32

`x=(k)/(y)\\x=(528)/(32)\\x=16.5`

So, when y=32, x=16.5