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Number 2 I need help on how to solve it

Number 2 I need help on how to solve it-example-1
User Jdpjamesp
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1 Answer

23 votes
23 votes

Let's simplify the following expression:


\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^(-4))^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^(-4)\text{z}^(-5)}{\text{ \lparen2x}^6\text{y}^3\text{z}^(-3))^2}

We get,


\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^(-4))^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }(6x^5y^(-4)z^(-5))/((2x^6y^3z^(-3))^2)
\text{ }((2x^4-y^6z^(-4))^2(6x^5y^(-4)z^(-5)))/((2x^2z^3)(2x^6y^3z^(-3))^2)
\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^(-4)\text{ + y}^(12)z^(-8))(6x^5y^(-4)z^(-5))}{(2x^2z^3)(4x^(12)y^6z^(-6))}
\text{ }\frac{24x^(13)y^(-4)z^(-5)\text{ - 24x}^9y^2z^(-9)\text{ + 6x}^5y^8z^(-13)}{8x^(14)y^6z^(-3)}

User Mina Wissa
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