Question

1. What is the spring constant of a spring that stretches 12 cm when an object weighing 24 Nis hung from it?

Answer 1

200 N/m

Explanation:

Given:

x = 12 cm = 0.12 m

F = 24 N

The force is given by the following equation:

`F=kx`

We substitute and calculate for k, which is ls spring constant , just like this:

`\begin{gathered} 24=k\cdot0.12 \\ \\ k=(24)/(0.12) \\ \\ k=200\text{ N/m} \end{gathered}`

The spring constant is 200 N/m