Question

Sodium and oxygen react to produce Sodium oxide. How many moles of sodium are needed to produce 2.83 grams of Sodium oxide

Answer 1

The moles of sodium needed to produce 2.83 grams of sodium oxide = 0.0914 moles.

Step-by-step explanation

Given:

Mass of sodium oxide produced = 2.83 grams

What to find:

The moles of sodium needed to produce 2.83 grams of sodium oxide.

Step-by-step solution:

Step 1: Step 2: Write a balance equation for the reaction.

4Na + O₂ -------> 2Na₂O

Step 2: Convert 2.83 grams sodium oxide to mole using the mole formula.

`Mole=\frac{Mass}{Molar\text{ }mass}`

The molar mass of Na2O = 61.9789 g/mol

So, putting mass = 2.83 g and molar mass = 61.9798 g/mol, we have;

`Mole=\frac{2.83g}{61.9798\text{ }g\text{/}mol}=0.0457\text{ }mol`

Step 3: Calculate the mole of sodium needed using the balance equation and the mole of sodium oxide produced.

From the balanced equation;

4 moles Na produces 2 moles Na₂O

So, the moles of Na needed to produce 0.0457 moles Na₂O will be

`\frac{0.0457mol\text{ }Na₂O}{2\text{ }mol\text{ }Na₂O}*4\text{ }mol\text{ }Na=0.0914\text{ }mol\text{ }Na`

The moles of sodium needed to produce 2.83 grams of sodium oxide = 0.0914 moles