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4 votes
How do you solve 18b2c-12ab3+30ab?

User Maksimr
by
6.5k points

2 Answers

7 votes


6b(3* 2c - 2a * 3 + 5a) \\ \\ 6b(6c - 6a + 5a) \\ \\ 6b(6c - a)
User Anthi
by
6.6k points
4 votes
18b²c - 12ab³ + 30ab

We're simply just trying to factor this out.

So : What goes into ALL of these numbers?

6 does! :)

So, divide everything by 6.

6(3b²c - 2ab³ + 5ab)

Now, what else goes into these numbers/variables? :)

b does! So, simply factor out b.

6b(3bc - 2ab² + 5a)
----------------------------

To check if this is correct, simplify this & see if it is the same as our original equation.

(6b · 3bc) + (6b · -2ab²) + (6b · 5a)

Simplify.

(18b²c) + (-12ab³) + (30a)

Get rid of the parenthesis.

18b²c - 12ab³ + 30a = 10b²c - 12ab³ + 30ab (Our original equation)

Therefore, 6b(3bc - 2ab² + 5a) is our correct answer.

~Hope I helped!~
User Rugnar
by
6.6k points
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