Question

A small gasoline shop engine develops 60 hp at 2000 rpm. At 2300 rpm its power output is increased by 15%. What actual horsepower does it produce at 2300 rpm?The engine produces hp___at 2300 rpm(Type a whole number or an exact decimal. If the decimal does not terminate, round to one decimal place.)

Answer 1

It is given that the output of 60 hp at 2000 rpm is increased by 15% at 2300 rpm.

It is required to find the actual horsepower at 2300 rpm.

To do this, find the value of the 15% increase of 60:

`(100+15)/(100)*60=(115)/(100)*60=69\text{ hp}`

The engine produces 69 hp at 2300 rpm.