Question

For this question use the balanced equation shown:Mg3N2 + 6 H2O → 3 Mg(OH)2 + 2 NH3When 2.00 moles of H2O are reacted, how many grams of NH3 are produced?Group of answer choices5.67 g10.0 g11.3 g34.0 g102 g

Answer 1

11.3 g of NH3 are produced. (The third option)

Step-by-step explanation:

1st) From the balanced equation we know that from 6 moles of H2O, 2 moles of NH3 are produced.

2nd) Using the molar mass of NH3 (17.031g/mol) we can convert moles to grams:

`2mol*(17.031g)/(1mol)=34.062g`

Now we know that when 6 moles of H2O react, 34.062g of NH3 are produced.

3rd) To calculate the grams of NH3 that will be produced from 2.00 moles of H2O, we can use a mathematical rule of three and the relation between H2O and NH3 that we found in the previous point:

`\begin{gathered} 6moles\text{ H}_2\text{O-}34.062g\text{ NH}_3 \\ 2moles\text{H}_2\text{O-x =}\frac{2moles\text{H}_2\text{O}*34.062g\text{ NH}_3}{6moles\text{ H}_2\text{O}} \\ x=11.3g\text{ NH}_3 \end{gathered}`

So, 11.3 grams of NH3 are produced.