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A box is being pulled to the right on flat ground with a force of 112 N at an angle of 42° to the horizontal. What is the x-component of the force of tension? 39 N 75 N 83 N 112 N

User Alezis
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1 Answer

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Hey there!

The answer is 83 N

How?-
cos(42°) = x-component / F ⇒ x-component = Fcos(42°) = 112N*0.743 = 83.2 N
User Mariuxi
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