Two points on this line are (2,30) and (4,60). Check that for yourself.
60-30
Then the slope of the line through these points is m = ----------- = 30/2 = 15. 4-2
Now find the equation of the line. Use the point-slope format:
y-k = m(x-h), where (h,k) is a point on the line. Let (2,30) be (h,k). Then:
y-30 = 15(x-2), or y-30 = 15x -30
Adding 30 to both sides of this eqn leaves us with y=15x. This is the equation of the line thru those points.