Question

How far horizontally has the car traveled in 15 seconds

Answer 1

Given,

The acceleration of the car,

`a=2.5m/s^2`

The angle of inclination,

`\theta=5.9^o`

Let the distance travelled along inclined be s at time t=15 s

Thus,

`\begin{gathered} s=(1)/(2)at^2 \\ \Rightarrow s=(1)/(2)*2.5*15^2=281.25\text{ m} \end{gathered}`

Along horizontal the distance travelled is

x=scos5.9=281.25cos5.9=279.76 m