Question

Solve the following quadratic equation by using the quadratic formula. If needed, submit your answer as a fraction reduced to lowest terms or round your answer to two decimal places

Answer 1

Solve the following quadratic equation by using the quadratic formula

`3z^2-2z=0`
`z=(-b\pm√(b^2-4ac))/(2a)`
`\begin{gathered} 3z^2-2z+0=0 \\ a=3,b=-2,c=0 \end{gathered}`
`\begin{gathered} z=(-(-2)\pm√((-2)^2-4(3)(0)))/(2(3)) \\ z=(2\pm√(4))/(6) \\ z=(2\pm2)/(6) \\ z=(2+2)/(6),(2-2)/(6) \\ z=(4)/(6),(0)/(6) \\ x=(2)/(3),0 \end{gathered}`

Therefore the correct answer is

`z=(2)/(3),0`