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Given that P = (-4, 11) and Q = (-5, 8), find the component form and magnitude of vector QP

2 Answers

3 votes

Answer:

<1, 3>, square root of ten

Explanation:

User Eileen Tao
by
9.2k points
6 votes
The given points are
P = (-4,11)
Q = (-5,8)

The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3

The vector QP is
(1,3) or

\vec{QP} = \hat{i} + 3\hat{j}

The magnitude of the vector is
√(1² + 3²) = √(10)

Answer:

\vec{QP} = \hat{i}+3\hat{j} \,\, or \,\, (1,3)
The magnitude is √(10).

User DkAngelito
by
8.1k points

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