Question

What point in the feasible region maximizes the objective function constraints: x>=0 y>=0 -x+3>=y y<=1/3 x+1 Objective function: C=5x-4y Please explain!

Answer 1

So, the maximum of C is 15 at (3,0) and the minimum value is 0 at (0,0)

Explanation:

When you graph all of the constraint functions, the vertices of the shape that is made are at the points above. Now you plug those points into the function equation C=5x-4y and see where you get a max or min.

(0,1)

(1.5,1.5)

(0,0)

(3,0)

(1,1)=C=1

(1.5,1.5)=C=1.5

(0,0)=C=0

(3,0)=C=15

So, the maximum of C is 15 at (3,0) and the minimum value is 0 at (0,0)

Answer 2

c= o because the c=5x-4y the x is 0 and the y is 0 so your answer is zero