Question

Find the equation of the straight line passing through the point (3,5)

which is perpendicular to the line y = 3x + 2

Answer 1

y = -1/3x+6 ---> 3y = -x+10 ---> x+ 3y = 10

Explanation:

Answer 2

The slope/gradient of the perpendicular line is -1/3 since 3*m2=-1. Now use the slope-point method to get:

y-5=-1/3(x-3)

3y-15= -x+3

x+3y=18 or you could rearrange it as y=-(1/3x)+6