Question

A species of shark has the length of their teeth controlled by a gene ‘T’ where long is dominant to short. A homozygous long-toothed shark (TT) and a heterozygous long-toothed shark (Tt) have an allele frequency of T: 0.75, t: 0.25. If they have 10 offspring and 6 are homozygous long-toothed sharks and 4 are heterozygous long-toothed sharks, what is the new allele frequency?A. T: 0.8 t: 0.2B. T: 0.5 t: 0.5C. T: 0.6 t: 0.4D. T: 1 t: 0

Answer 1

Step-by-step explanation

We have 10 offspring, 6 are homozygous long-toothed sharks and 4 are heterozygous long-toothed sharks. The homozygous long-toothed sharks is 80% = 0.8 and the heterozygous long-toothed sharks is 20% = 0.2

Therefore the answer is A.

Answer

A. T: 0.8 t: 0.2