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AcellusUse the value of x to find themeasure of Angle 1.x = 25Z1 = [?]° 22 = [ 1°5x - 5/2x + 10Enter
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AcellusUse the value of x to find themeasure of Angle 1.x = 25Z1 = [?]° 22 = [ 1°5x - 5/2x + 10Enter

AcellusUse the value of x to find themeasure of Angle 1.x = 25Z1 = [?]° 22 = [ 1°5x-example-1
User James Bloomer
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1 Answer

29 votes
29 votes

x = 25

Therefore


\begin{gathered} \angle1=5x-5 \\ \angle1=5(25)-5 \\ \angle1=125-5 \\ \angle1=120^(\circ) \end{gathered}
\begin{gathered} \angle2=2x+10 \\ \angle2=2(25)+10 \\ \angle2=50+10 \\ \angle2=60^(\circ) \end{gathered}

User Jamika
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