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Find the solutions of the following trigonometric equation in the interval [0, 2π).
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35 votes
35 votes
Find the solutions of the following trigonometric equation in the interval [0, 2π).

Find the solutions of the following trigonometric equation in the interval [0, 2π).-example-1
User Ryan Tenney
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1 Answer

28 votes
28 votes

Given the equation:


4x-2\sqrt[]{3}\sin \sin x+2\sin \sin x+\sqrt[]{3}-4=0

Simplifying the given equation:


\begin{gathered} 4x-(2\sqrt[]{3}-2)\sin \sin x+\sqrt[]{3}-4=0 \\ 4x-(2\sqrt[]{3}-2)\sin \sin x=4-\sqrt[]{3} \\ 2x-(\sqrt[]{3}-1)\sin \sin x=\frac{(4-\sqrt[]{3})}{2}_{} \end{gathered}

User Md Abdul Gafur
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