Question

Hi, can you help me to find the Nearest tenth.And measure of acute angle that the given lineforms with a horizontal line, please!

Answer 1

Step 1:

Write the equation of the line in the form of y = mx + c

m = slope

Step 2

`\begin{gathered} \text{Slope = tan}\theta \\ \text{m = tan}\theta \end{gathered}`

Step 3

From the equation

`\begin{gathered} \text{y = }(1)/(2)x\text{ + 4} \\ m\text{ = }(1)/(2) \end{gathered}`

Step 4:

`\begin{gathered} m\text{ = tan}\theta \\ (1)/(2)\text{ = tan}\theta \\ \theta=tan^(-1)((1)/(2)) \\ \theta\text{ = 26.6} \end{gathered}`

Final answer

The measure of acute angle = 26.6