Question

Find the area of the figure below, composed of a rectangle with two semicirlces removed. Round to the nearest tenths place.

Answer 1

The area of the shape is 39.4 square units

Here, we want to find the area of the given shape

As we can see, we have a full rectangle that measures 13 by 4

The full triangle has two semi-circles removed from it, one on either side

So what we have to do here is to subtract the areas of the two semicircles from the area of the rectangle

Since two semi-circles make a circle, we simple are going to subtract the area of a circle from the area of the recatangle

The measure 4 stands for the diameter of the semi-circles. To get the radius, we divide this diameter by 2 which is 4/2 = 2

Thus, we have it that;

`\begin{gathered} \text{Area of shape = Area of rectangle - Area of circle} \\ \text{Area of rectangle = L }*\text{ B = 13 }*\text{ 4 = 52 sq.units} \\ \text{Area of circle = }\pi\text{ }* r^2\text{ = }\pi\text{ }*2^2\text{ = 4}\pi\text{ = 12.57 sq.units} \\ \text{Area of shape = 52-12.57 = 39.43 sq.units} \end{gathered}`