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35 votes
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User Adam Vandenberg
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1 Answer

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20 votes

We will make use of the Trigonometry ratio to solve this question.

From the figure provided;

Hypotenuse side = 6

Opposite side = y

Adjacent side = x

Given angle = 60 degrees

To find side x, the suitable Trigonometry ratio to be used is the Cosine.

Thus, we have;


\begin{gathered} \text{Cos}\theta=\frac{\text{Adjacent}}{\text{Hypotenuse}} \\ \text{Cos}60=(x)/(6) \\ \text{cross}-\text{multiply} \\ x=6*\cos 60 \\ x=6*0.5 \\ x=3 \end{gathered}

To find side y, the suitable Trigonometry ratio to be used is the Sine.

Thus, we have;


\begin{gathered} Sin\theta=\frac{\text{Opposite}}{\text{Hypotenuse}} \\ \text{Sin}60=(y)/(6) \\ cross-multiply \\ y=6*\sin 60 \\ y=6*\frac{\sqrt[]{3}}{2} \\ y=3\sqrt[]{3} \end{gathered}

Hence, the values of x and y are:


x=3;y=3\sqrt[]{3}

User Veera Nagireddy
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