Question

A culture of 1.08×1015 bacteria is in petri dish A. A culture of 2.7×1011 bacteria is in petri dish B.

How many times greater is the number of bacteria in petri dish A than petri dish B?

PLEASE ANSWER QUICKLY

Answer 1

1.08×10^15
------------------ = 0.4 x 10^4 = 4000
2.7×10^11

answer
4000 times greater

Answer 2

Answer:The number of bacteria in petri dish A is 4000 times greater than petri dish B.

Explanation:

Culture of bacteria in petri dish A=
`1.08*10^(15)`

Culture of bacteria in petri dish B=
`2.7*10^(11)`

Dividing culture of bacteria in petri dish A bu culturebacteria in petri dish B ,we get

`(1.08*10^(15))/(2.7*10^(11))=(108*10^(15-11))/(270)\\\\=(108)/(270)*10^(4)=0.4*10^4=4000`

Therefore, the number of bacteria in petri dish A is 4000 times greater than petri dish B.