Question

If you have 6000 Oxygen (O) atoms how many grams of Oxygen (O) do you have ?O 1.59x10-19 gramsO 5.78x1028 gramsO 6.22x10-22 gramsO 9.96x10-21 gramsO 3.61x1027 grams

Answer 1

`\text{ The mass of oxygen in grams is 1.59}*10^(-19)\text{ grams}`

Step-by-step explanation

Given that:

`\text{ The number of atoms of oxygen is 6000}`

To calculate the amount of oxygen in grams, follow the steps below

Step 1: Find the number of moles using the below formula

`\text{ Mole }=\frac{number\text{ of atoms}}{Avogadro^(\prime)s\text{ number}}`

Recall, that the Avogadro's number is 6.022 x 10^23

`\begin{gathered} \text{ Mole }=(6000)/(6.022*10^(23)) \\ \\ \text{ Mole}=(6*10^3)/(6.022*10^(23)) \\ \\ \text{ Mole }=\text{ }(6)/(6.022)*10^(3-23) \\ 0.9963*10^(-20) \\ 9.9963*10^(-21)\text{ mole} \end{gathered}`

Step 2; Find the amount of oxygen in grams using the below formula

`\begin{gathered} \text{ Mole }=\frac{\text{ mass}}{\text{ molar mass}} \\ \text{ cross multiply} \\ \text{ mass }=\text{ mole }*\text{ molar mass} \end{gathered}`

Recall, that the molar mass of oxygen is 16 g/mol

`\begin{gathered} mass=\text{ mole }*\text{ molar mass} \\ \text{ mass }=\text{ 9.9963}*10^(-21)*\text{ 16} \\ \text{ mass }=\text{ 9.9963}*16*10^(-21) \\ \text{ mass }=\text{ 159.94}*10^(-21) \\ \text{ mass }=\text{ 1.59}*10^2*10^(-21) \\ \text{ mass }=\text{ 1.59}*10^(2-21) \\ \text{ mass }=\text{ 1.59}*10^(-19)\text{ grams} \end{gathered}`