Write the equation in standard form for the circle x² + y²- 18y - 19 = 0.

Kopecs asked Sep 12, 2023

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Kopecs asked Sep 12, 2023

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20 votes

$\begin{gathered} x^2+y^2-18y-19=0 \\ x^2+(y^2-18y+81)-81-19=0 \\ x^2+(y-9)^2=100 \\ (x-0)^2+(y-9)^2=10^2 \end{gathered}$

Swanand answered Sep 16, 2023

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