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A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the lightbulb?
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A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the lightbulb?

User Shahil Mohammed
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1 Answer

4 votes

Current = voltage / resistance

= 110 v / 285 Ω

= 0.386 Ampere (rounded)
User Michael Grigsby
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