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A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the lightbulb?
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Feb 28, 2018
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A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the lightbulb?
Physics
college
Shahil Mohammed
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Current = voltage / resistance
= 110 v / 285 Ω
=
0.386 Ampere
(rounded)
Michael Grigsby
answered
Mar 4, 2018
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Michael Grigsby
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