Question

10. Iron (III) oxide is used as a source material for iron in steel manufacturing. The density ofiron (III) oxide is 5,242 g/cm'.a. If a plant needed to transport 88,915 kg of iron(III) oxide every day for operations, whatvolume of iron(III) oxide is transported (in Liters)?b. If a standard, tandem axle dump truck can haul 15 tons of ore and the mine is one dayaway from the manufacturing site, how many dump trucks are needed each day?c. Each dump truck must drive 285 miles from the source to the manufacturing site. If eachtruck gets 7.8 miles per gallon of gas and the price of gas is $3.95 per gallon, what is thefuel cost, per day, for the manufacturing plant?

Answer 1

$144.33

Explanations:

c) From the information given, we are told that each dump truck must drive 285 miles from the source to the manufacturing site.

If each truck gets 7.8 miles per gallon of gas, the total number of gallons needed for the trip is calculated as:

`\text{Total number of gallons=}\frac{\text{Total miles traveled}}{Miles\text{ traveled per gallon of gas}}`

Substitute the given parameters into the formula to have:

`\begin{gathered} \text{Total number of gallons=}\frac{285miles}{7.8miles\text{/gallon}} \\ \text{Total number of gallons=}36.54\text{gallons} \end{gathered}`

Hence total gallons that cover the whole trip is approximately 36.54 gallons

Next is to calculate the fuel cost, per day, for the manufacturing plant if the price of gas is $3.95 per gallon

`\begin{gathered} \text{Cost of}36.54gallons=36.54*3.95 \\ \text{Cost of}36.54gallons=\$144.333 \end{gathered}`

Therefore, the fuel cost, per day, for the manufacturing plant is $144.33