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If f(x) = -x² - 1, andg(x) = x+5, theng(f(x)) = [? ]x² + [ ]

User Scott Langham
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We are ask to make a function composition, where we replace the value of "x" in the g-function by the value of "f":


\begin{gathered} f(x)=-x^2-1 \\ g(x)=x+5 \\ g(f)=(f)+5 \\ g(f)=(-x^2-1)+5 \\ g(f)=-x^2+4 \end{gathered}

Because the question asks for g(f), we have to replace the entire "f" function in any place where x appears in "g". In detail, g=x+5, then we have to replace the first term x, by the whole f=-x^2-1. So we got g(f)=f+5 or g(f)=(-x^2-1)+5, finally we break the parenthesis and add -1+5: g(f)=-x^2+4

Hence, the answer is -x^2+4

If f(x) = -x² - 1, andg(x) = x+5, theng(f(x)) = [? ]x² + [ ]-example-1
User Joshua G
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