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What is the critical angle if a ray of light in Sodium Chloride (n=1.54) is headed into Quartz (n=1.46)?0.649⁰0.948°71.4°40.5°
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19 votes
19 votes
What is the critical angle if a ray of light in Sodium Chloride (n=1.54) is headed into Quartz (n=1.46)?0.649⁰0.948°71.4°40.5°

User BerndK
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1 Answer

9 votes
9 votes

We can find the critical angle as follows:


\begin{gathered} \theta_c=sin^(-1)((n2)/(n1)) \\ \theta_c=sin^(-1)((1.46)/(1.54)) \\ \theta_c\approx71.4 \end{gathered}

Answer:

71.4⁰

User Ponytech
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