19.0k views
2 votes
Is this function even, odd, or neither?

Is this function even, odd, or neither?-example-1

2 Answers

3 votes
when a function is even, they have symmetry with respect to the y-axis, what does that mean? well, the graph to the right-side of the y-axis is just a mirror image of the graph to the left-side of the y-axis.

when a function is odd, the symmetry is with respect to the origin, meaning, the graph to the right-side of the y-axis, is a mirror image of the one on the left-bottom-upside-down. So, you take a photo of the right-side graph,flip it over the x-axis, and then flip it again over the y-axis.

now, this one shows neither of those behaviours.
User Reallynice
by
6.0k points
2 votes

Answer:

The given function is neither even nor odd.

Explanation:

A function is an even function if


f(-x)=f(x)

A function is an odd function if


f(-x)=-f(x)

From the given graph it is clear that graph is passing though the points (-3,2), (-1,2), (0,1/2), (1/2,0), (1,-1), (2,-1) and (3,1).

Here,


f(3)=1


f(-3)=2


f(-3)\\eq f(3) and
f(-3)\\eq -f(3)

Since
f(-x)\\eq f(x) and
f(-x)\\eq -f(x), therefore the given function is neither even nor odd.

User Chris Pierce
by
6.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.