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How do I write this as a single rational expression?


(1)/(p-2) - (1)/(p+2)

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\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\\\ -------------------------------\\\\ \cfrac{1}{p-2}-\cfrac{1}{p+2}\impliedby \textit{so let's use the }\stackrel{LCD}{(p-2)(p+2)} \\\\\\ \cfrac{(p+2)~~-~~(p-2)}{(p-2)(p+2)}\implies \cfrac{\underline{p}+2~~\underline{-p}+2}{(p-2)(p+2)}\implies \cfrac{4}{p^2-2^2}\implies \cfrac{4}{p^2-4}
User Loek Bergman
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