Question

What is the answer to the problem for sin, sec, tan. I don’t really need a detailed explanation just the answer. Thank you.

Answer 1

`\begin{gathered} \sin(\theta)=-0.35 \\ \\ sec(\theta)=-1.07 \\ \\ \tan(\theta)=0.38 \end{gathered}`

Explanation:

Remember that for a given terminal point of an angle, we define those trigonometric functions as following:

`\begin{gathered} \sin(\theta)=(y)/(√(x^2+y^2)) \\ \\ sec(\theta)=(√(x^2+y^2))/(x) \\ \\ \tan(\theta)=(y)/(x) \end{gathered}`

This way, we'll have that:

`\begin{gathered} \sin(\theta)=-0.35 \\ \\ sec(\theta)=-1.07 \\ \\ \tan(\theta)=0.38 \end{gathered}`