Let
f(x) = x³ - x² + x - 1
g(x) = x² - 1
By the remainder theorem, f(1) = 1 -1 + 1 - 1 = 0
Therefore (x-1) is a factor.
Perform synthetic division.
1 | 1 -1 1 -1
1 0 1
--------------
1 0 1 0
Therefore,
f(x) = (x-1)(x²+1)
Also,
g(x) = (x+1)(x-1)
Answer: b.
The least common multiple for f(x) and g(x) is (x + 1)(x - 1)(x² + 1).