Question

A chemist determined by measurements that 0.0350 moles of aluminum participated in a chemical reaction. Calculate the mass of the aluminum that participated in the chemical reaction. Be sure your Answer has the correct number of significant digits

Answer 1

We know that 0.0350 moles of aluminum participated in a chemical reaction and we must find the mass of the aluminum that participated in the reaction.

In order to find the mass of the aluminum that participated we must use the molar mass of this element:

- Molar mass of Aluminum: 26.981539 g/mol

Then, we need to use the next formula:

`\text{ Mass that reacted}=\text{ molar mass}\cdot\text{ number of moles}`

In this case, the number of moles is 0.0350

Now, we must replace the values in the formula

`\text{Mass that reacted}=26.981539\frac{g}{\text{mol}}\cdot0.0350\text{mol}`

Finally, we must simplify the equation

`\text{ Mass that reacted}=9.44353865\cdot10^(-1)g`

ANSWER:

Using the correct number of significant digits:

`9.44\cdot10^(-1)`