Question

Please help!! at what rate is his distance increasing from home plate…

Answer 1

To determine the distance of increase rate of a baseball:

Using pythagoras theorem:

6^2+90^2) when t = 0

2 (100.6) dx/dt = 90*-20

dx/dt = -8.94 ft/s

`\begin{gathered} x^2=(65-22t)^2+90^2 \\ \text{when you differentiate} \\ 2x(dx)/(dt)=2(65-22t)^{}(-22) \end{gathered}`

At the rate of distance covered by the baseball, hence

`\begin{gathered} x^2=(65-22t)^2+90^2 \\ x^2=(65-22(0))^2+90^{2\text{ }}\text{ when t = 0} \\ x^2=65^2+90^2 \\ x=\sqrt[]{65^2+90^2} \\ x=\sqrt[]{12325} \\ x=111.02 \end{gathered}`