Question

A. 11 square root of 3B. 11 square root of 3 divided by 3C. 22 square root of 2D. 22

Answer 1

- The way to solve the question is to use SOHCAHTOA.

- This is given below:

`\begin{gathered} \text{ We first need to find the Hypotenuse of the 45-45-90 triangle.} \\ (11)/(Hypotenuse)=\sin45 \\ \\ \therefore Hypotenuse=(11)/(\sin45)=11√(2) \\ \\ \\ \text{ The Hypotenuse of the 45-45-90 triangle is the Opposite of the 30-60-90 triangle} \\ \text{ Thus, we can find }x\text{ as follows:} \\ \\ (11√(2))/(x)=\cos60 \\ \\ (11√(2))/(\cos60)=x \\ \\ x=(11√(2))/((1)/(2))=2*11√(2) \\ \\ x=22√(2) \end{gathered}`

- Thus, the answer is

`x=22√(2)`